Solve for x
x=3\left(y+1\right)
Solve for y
y=\frac{x-3}{3}
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3x=9+9y
Add 9y to both sides.
3x=9y+9
The equation is in standard form.
\frac{3x}{3}=\frac{9y+9}{3}
Divide both sides by 3.
x=\frac{9y+9}{3}
Dividing by 3 undoes the multiplication by 3.
x=3y+3
Divide 9+9y by 3.
-9y=9-3x
Subtract 3x from both sides.
\frac{-9y}{-9}=\frac{9-3x}{-9}
Divide both sides by -9.
y=\frac{9-3x}{-9}
Dividing by -9 undoes the multiplication by -9.
y=\frac{x}{3}-1
Divide 9-3x by -9.
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