Solve for x
x=\frac{8y}{3}+3
Solve for y
y=\frac{3\left(x-3\right)}{8}
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3x=9+8y
Add 8y to both sides.
3x=8y+9
The equation is in standard form.
\frac{3x}{3}=\frac{8y+9}{3}
Divide both sides by 3.
x=\frac{8y+9}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{8y}{3}+3
Divide 9+8y by 3.
-8y=9-3x
Subtract 3x from both sides.
\frac{-8y}{-8}=\frac{9-3x}{-8}
Divide both sides by -8.
y=\frac{9-3x}{-8}
Dividing by -8 undoes the multiplication by -8.
y=\frac{3x-9}{8}
Divide 9-3x by -8.
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