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3x=8y
Add 8y to both sides. Anything plus zero gives itself.
\frac{3x}{3}=\frac{8y}{3}
Divide both sides by 3.
x=\frac{8y}{3}
Dividing by 3 undoes the multiplication by 3.
-8y=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
\frac{-8y}{-8}=-\frac{3x}{-8}
Divide both sides by -8.
y=-\frac{3x}{-8}
Dividing by -8 undoes the multiplication by -8.
y=\frac{3x}{8}
Divide -3x by -8.