Solve for x
x=2y+\frac{25}{2}
Solve for y
y=\frac{x}{2}-\frac{25}{4}
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3x-4y-25-x=0
Subtract x from both sides.
2x-4y-25=0
Combine 3x and -x to get 2x.
2x-25=4y
Add 4y to both sides. Anything plus zero gives itself.
2x=4y+25
Add 25 to both sides.
\frac{2x}{2}=\frac{4y+25}{2}
Divide both sides by 2.
x=\frac{4y+25}{2}
Dividing by 2 undoes the multiplication by 2.
x=2y+\frac{25}{2}
Divide 4y+25 by 2.
-4y-25=x-3x
Subtract 3x from both sides.
-4y-25=-2x
Combine x and -3x to get -2x.
-4y=-2x+25
Add 25 to both sides.
-4y=25-2x
The equation is in standard form.
\frac{-4y}{-4}=\frac{25-2x}{-4}
Divide both sides by -4.
y=\frac{25-2x}{-4}
Dividing by -4 undoes the multiplication by -4.
y=\frac{x}{2}-\frac{25}{4}
Divide -2x+25 by -4.
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y = 3x + 4
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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