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Solve for x, y, k
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x=\frac{4}{3}y+\frac{13}{3}
Solve 3x-4y-13=0 for x.
8\left(\frac{4}{3}y+\frac{13}{3}\right)-11y-33=0 2\left(\frac{4}{3}y+\frac{13}{3}\right)-3y+k=0
Substitute \frac{4}{3}y+\frac{13}{3} for x in the second and third equation.
y=5 k=-\frac{26}{3}+\frac{1}{3}y
Solve these equations for y and k respectively.
k=-\frac{26}{3}+\frac{1}{3}\times 5
Substitute 5 for y in the equation k=-\frac{26}{3}+\frac{1}{3}y.
k=-7
Calculate k from k=-\frac{26}{3}+\frac{1}{3}\times 5.
x=\frac{4}{3}\times 5+\frac{13}{3}
Substitute 5 for y in the equation x=\frac{4}{3}y+\frac{13}{3}.
x=11
Calculate x from x=\frac{4}{3}\times 5+\frac{13}{3}.
x=11 y=5 k=-7
The system is now solved.