Solve 3x-4y=-6quad2x+4y+16

$$3 x - 4 y = - 6 \quad 2 x + 4 y + 16$$

Solve for x

$$x=\frac{8\left(y+2\right)}{15}$$

Steps for Solving Linear Equation

Multiply -6 and 2 to get -12.

$$3x-4y=-12x+4y+16$$

Add 12x to both sides.

$$3x-4y+12x=4y+16$$

Combine 3x and 12x to get 15x.

$$15x-4y=4y+16$$

Add 4y to both sides.

$$15x=4y+16+4y$$

Combine 4y and 4y to get 8y.

$$15x=8y+16$$

Divide both sides by 15.

$$\frac{15x}{15}=\frac{8y+16}{15}$$

Dividing by 15 undoes the multiplication by 15.

$$x=\frac{8y+16}{15}$$

Solve for y

$$y=\frac{15x}{8}-2$$

Steps for Solving Linear Equation

Multiply -6 and 2 to get -12.

$$3x-4y=-12x+4y+16$$

Subtract 4y from both sides.

$$3x-4y-4y=-12x+16$$

Combine -4y and -4y to get -8y.

$$3x-8y=-12x+16$$

Subtract 3x from both sides.

$$-8y=-12x+16-3x$$

Combine -12x and -3x to get -15x.

$$-8y=-15x+16$$

The equation is in standard form.

$$-8y=16-15x$$

Divide both sides by -8.

$$\frac{-8y}{-8}=\frac{16-15x}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$y=\frac{16-15x}{-8}$$

Divide -15x+16 by -8.

$$y=\frac{15x}{8}-2$$