Solve for x
x=\frac{4y-29}{3}
Solve for y
y=\frac{3x+29}{4}
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3x+29=4y
Add 4y to both sides. Anything plus zero gives itself.
3x=4y-29
Subtract 29 from both sides.
\frac{3x}{3}=\frac{4y-29}{3}
Divide both sides by 3.
x=\frac{4y-29}{3}
Dividing by 3 undoes the multiplication by 3.
-4y+29=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
-4y=-3x-29
Subtract 29 from both sides.
\frac{-4y}{-4}=\frac{-3x-29}{-4}
Divide both sides by -4.
y=\frac{-3x-29}{-4}
Dividing by -4 undoes the multiplication by -4.
y=\frac{3x+29}{4}
Divide -3x-29 by -4.
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Limits
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