Solve for x
x=\frac{2y-z+4}{3}
Solve for y
y=\frac{3x+z-4}{2}
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3x+z=4+2y
Add 2y to both sides.
3x=4+2y-z
Subtract z from both sides.
3x=2y-z+4
The equation is in standard form.
\frac{3x}{3}=\frac{2y-z+4}{3}
Divide both sides by 3.
x=\frac{2y-z+4}{3}
Dividing by 3 undoes the multiplication by 3.
-2y+z=4-3x
Subtract 3x from both sides.
-2y=4-3x-z
Subtract z from both sides.
-2y=4-z-3x
The equation is in standard form.
\frac{-2y}{-2}=\frac{4-z-3x}{-2}
Divide both sides by -2.
y=\frac{4-z-3x}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{z}{2}+\frac{3x}{2}-2
Divide 4-3x-z by -2.
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