Solve for x
x=\frac{y+729}{243}
Solve for y
y=243\left(x-3\right)
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3x-\frac{1}{81}y=9
Calculate \frac{1}{3} to the power of 4 and get \frac{1}{81}.
3x=9+\frac{1}{81}y
Add \frac{1}{81}y to both sides.
3x=\frac{y}{81}+9
The equation is in standard form.
\frac{3x}{3}=\frac{\frac{y}{81}+9}{3}
Divide both sides by 3.
x=\frac{\frac{y}{81}+9}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{y}{243}+3
Divide 9+\frac{y}{81} by 3.
3x-\frac{1}{81}y=9
Calculate \frac{1}{3} to the power of 4 and get \frac{1}{81}.
-\frac{1}{81}y=9-3x
Subtract 3x from both sides.
\frac{-\frac{1}{81}y}{-\frac{1}{81}}=\frac{9-3x}{-\frac{1}{81}}
Multiply both sides by -81.
y=\frac{9-3x}{-\frac{1}{81}}
Dividing by -\frac{1}{81} undoes the multiplication by -\frac{1}{81}.
y=243x-729
Divide 9-3x by -\frac{1}{81} by multiplying 9-3x by the reciprocal of -\frac{1}{81}.
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