Solve 3x*2x=192

$$3 x \times 2 x = 192$$

Solve for x

$$x=4\sqrt{2}\approx 5.656854249$$

$$x=-4\sqrt{2}\approx -5.656854249$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$3x^{2}\times 2=192$$

Multiply 3 and 2 to get 6.

$$6x^{2}=192$$

Divide both sides by 6.

$$x^{2}=\frac{192}{6}$$

Divide 192 by 6 to get 32.

$$x^{2}=32$$

Take the square root of both sides of the equation.

$$x=4\sqrt{2} x=-4\sqrt{2}$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$3x^{2}\times 2=192$$

Multiply 3 and 2 to get 6.

$$6x^{2}=192$$

Subtract 192 from both sides.

$$6x^{2}-192=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 6 for a, 0 for b, and -192 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 6\left(-192\right)}}{2\times 6}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 6\left(-192\right)}}{2\times 6}$$

Multiply -4 times 6.

$$x=\frac{0±\sqrt{-24\left(-192\right)}}{2\times 6}$$

Multiply -24 times -192.

$$x=\frac{0±\sqrt{4608}}{2\times 6}$$

Take the square root of 4608.

$$x=\frac{0±48\sqrt{2}}{2\times 6}$$

Multiply 2 times 6.

$$x=\frac{0±48\sqrt{2}}{12}$$

Now solve the equation x=\frac{0±48\sqrt{2}}{12} when ± is plus.

$$x=4\sqrt{2}$$

Now solve the equation x=\frac{0±48\sqrt{2}}{12} when ± is minus.

$$x=-4\sqrt{2}$$

The equation is now solved.

$$x=4\sqrt{2} x=-4\sqrt{2}$$