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Solve for x (complex solution)
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3t^{2}-96t-256=0
Substitute t for x^{2}.
t=\frac{-\left(-96\right)±\sqrt{\left(-96\right)^{2}-4\times 3\left(-256\right)}}{2\times 3}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 3 for a, -96 for b, and -256 for c in the quadratic formula.
t=\frac{96±64\sqrt{3}}{6}
Do the calculations.
t=\frac{32\sqrt{3}}{3}+16 t=-\frac{32\sqrt{3}}{3}+16
Solve the equation t=\frac{96±64\sqrt{3}}{6} when ± is plus and when ± is minus.
x=-\sqrt{\frac{32\sqrt{3}}{3}+16} x=\sqrt{\frac{32\sqrt{3}}{3}+16} x=-i\sqrt{-\left(-\frac{32\sqrt{3}}{3}+16\right)} x=i\sqrt{-\left(-\frac{32\sqrt{3}}{3}+16\right)}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.
3t^{2}-96t-256=0
Substitute t for x^{2}.
t=\frac{-\left(-96\right)±\sqrt{\left(-96\right)^{2}-4\times 3\left(-256\right)}}{2\times 3}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 3 for a, -96 for b, and -256 for c in the quadratic formula.
t=\frac{96±64\sqrt{3}}{6}
Do the calculations.
t=\frac{32\sqrt{3}}{3}+16 t=-\frac{32\sqrt{3}}{3}+16
Solve the equation t=\frac{96±64\sqrt{3}}{6} when ± is plus and when ± is minus.
x=4\sqrt{\frac{2\sqrt{3}}{3}+1} x=-4\sqrt{\frac{2\sqrt{3}}{3}+1}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for positive t.