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3\left(x^{2}y+5xy-24y\right)
Factor out 3.
y\left(x^{2}+5x-24\right)
Consider x^{2}y+5xy-24y. Factor out y.
a+b=5 ab=1\left(-24\right)=-24
Consider x^{2}+5x-24. Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx-24. To find a and b, set up a system to be solved.
-1,24 -2,12 -3,8 -4,6
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -24.
-1+24=23 -2+12=10 -3+8=5 -4+6=2
Calculate the sum for each pair.
a=-3 b=8
The solution is the pair that gives sum 5.
\left(x^{2}-3x\right)+\left(8x-24\right)
Rewrite x^{2}+5x-24 as \left(x^{2}-3x\right)+\left(8x-24\right).
x\left(x-3\right)+8\left(x-3\right)
Factor out x in the first and 8 in the second group.
\left(x-3\right)\left(x+8\right)
Factor out common term x-3 by using distributive property.
3y\left(x-3\right)\left(x+8\right)
Rewrite the complete factored expression.