Solve 3x^2x-2xy-5=0

$$3 x ^ { 2 } x - 2 x y - 5 = 0$$

Solve for y

$$y=\frac{3x^{2}}{2}-\frac{5}{2x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$3x^{3}-2xy-5=0$$

Subtract 3x^{3} from both sides. Anything subtracted from zero gives its negation.

$$-2xy-5=-3x^{3}$$

Add 5 to both sides.

$$-2xy=-3x^{3}+5$$

The equation is in standard form.

$$\left(-2x\right)y=5-3x^{3}$$

Divide both sides by -2x.

$$\frac{\left(-2x\right)y}{-2x}=\frac{5-3x^{3}}{-2x}$$

Dividing by -2x undoes the multiplication by -2x.

$$y=\frac{5-3x^{3}}{-2x}$$

Divide -3x^{3}+5 by -2x.

$$y=\frac{3x^{2}}{2}-\frac{5}{2x}$$