Skip to main content
Factor
Tick mark Image
Evaluate
Tick mark Image
Graph

Similar Problems from Web Search

Share

3x^{2}-84x+14=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-\left(-84\right)±\sqrt{\left(-84\right)^{2}-4\times 3\times 14}}{2\times 3}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-84\right)±\sqrt{7056-4\times 3\times 14}}{2\times 3}
Square -84.
x=\frac{-\left(-84\right)±\sqrt{7056-12\times 14}}{2\times 3}
Multiply -4 times 3.
x=\frac{-\left(-84\right)±\sqrt{7056-168}}{2\times 3}
Multiply -12 times 14.
x=\frac{-\left(-84\right)±\sqrt{6888}}{2\times 3}
Add 7056 to -168.
x=\frac{-\left(-84\right)±2\sqrt{1722}}{2\times 3}
Take the square root of 6888.
x=\frac{84±2\sqrt{1722}}{2\times 3}
The opposite of -84 is 84.
x=\frac{84±2\sqrt{1722}}{6}
Multiply 2 times 3.
x=\frac{2\sqrt{1722}+84}{6}
Now solve the equation x=\frac{84±2\sqrt{1722}}{6} when ± is plus. Add 84 to 2\sqrt{1722}.
x=\frac{\sqrt{1722}}{3}+14
Divide 84+2\sqrt{1722} by 6.
x=\frac{84-2\sqrt{1722}}{6}
Now solve the equation x=\frac{84±2\sqrt{1722}}{6} when ± is minus. Subtract 2\sqrt{1722} from 84.
x=-\frac{\sqrt{1722}}{3}+14
Divide 84-2\sqrt{1722} by 6.
3x^{2}-84x+14=3\left(x-\left(\frac{\sqrt{1722}}{3}+14\right)\right)\left(x-\left(-\frac{\sqrt{1722}}{3}+14\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 14+\frac{\sqrt{1722}}{3} for x_{1} and 14-\frac{\sqrt{1722}}{3} for x_{2}.
x ^ 2 -28x +\frac{14}{3} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 3
r + s = 28 rs = \frac{14}{3}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 14 - u s = 14 + u
Two numbers r and s sum up to 28 exactly when the average of the two numbers is \frac{1}{2}*28 = 14. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(14 - u) (14 + u) = \frac{14}{3}
To solve for unknown quantity u, substitute these in the product equation rs = \frac{14}{3}
196 - u^2 = \frac{14}{3}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = \frac{14}{3}-196 = -\frac{574}{3}
Simplify the expression by subtracting 196 on both sides
u^2 = \frac{574}{3} u = \pm\sqrt{\frac{574}{3}} = \pm \frac{\sqrt{574}}{\sqrt{3}}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =14 - \frac{\sqrt{574}}{\sqrt{3}} = 0.168 s = 14 + \frac{\sqrt{574}}{\sqrt{3}} = 27.832
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.