Solve 3x=3/2-3y*5

$$3 x = \frac { 3 } { 2 } - 3 y \cdot 5$$

Solve for x

$$x=\frac{1}{2}-5y$$

Steps for Solving Linear Equation

Multiply 3 and 5 to get 15.

$$3x=\frac{3}{2}-15y$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{\frac{3}{2}-15y}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{\frac{3}{2}-15y}{3}$$

Divide \frac{3}{2}-15y by 3.

$$x=\frac{1}{2}-5y$$

Solve for y

$$y=-\frac{x}{5}+\frac{1}{10}$$

Steps for Solving Linear Equation

Multiply 3 and 5 to get 15.

$$3x=\frac{3}{2}-15y$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{3}{2}-15y=3x$$

Subtract \frac{3}{2} from both sides.

$$-15y=3x-\frac{3}{2}$$

Divide both sides by -15.

$$\frac{-15y}{-15}=\frac{3x-\frac{3}{2}}{-15}$$

Dividing by -15 undoes the multiplication by -15.

$$y=\frac{3x-\frac{3}{2}}{-15}$$

Divide 3x-\frac{3}{2} by -15.

$$y=-\frac{x}{5}+\frac{1}{10}$$