Solve 3x+9geq15x+3

$$3 x + 9 \geq 15 x + 3$$

Solve for x

$$x\leq \frac{1}{2}$$

Solution Steps

Subtract 15x from both sides.

$$3x+9-15x\geq 3$$

Combine 3x and -15x to get -12x.

$$-12x+9\geq 3$$

Subtract 9 from both sides.

$$-12x\geq 3-9$$

Subtract 9 from 3 to get -6.

$$-12x\geq -6$$

Divide both sides by -12. Since -12 is negative, the inequality direction is changed.

$$x\leq \frac{-6}{-12}$$

Reduce the fraction \frac{-6}{-12} to lowest terms by extracting and canceling out -6.

$$x\leq \frac{1}{2}$$