Solve for x
x=-\frac{7y}{3}+12
Solve for y
y=\frac{36-3x}{7}
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3x=36-7y
Subtract 7y from both sides.
\frac{3x}{3}=\frac{36-7y}{3}
Divide both sides by 3.
x=\frac{36-7y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{7y}{3}+12
Divide 36-7y by 3.
7y=36-3x
Subtract 3x from both sides.
\frac{7y}{7}=\frac{36-3x}{7}
Divide both sides by 7.
y=\frac{36-3x}{7}
Dividing by 7 undoes the multiplication by 7.
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