Solve 3x+6+1/2+8/9=100y+1/2-8/10*0.3

$$3 x + 6 + \frac { 1 } { 2 } + \frac { 8 } { 9 } = 100 y + \frac { 1 } { 2 } - \frac { 8 } { 10 } \times 0.3$$

Solve for x

$$x=\frac{100y}{3}-\frac{1604}{675}$$

Steps for Solving Linear Equation

Add 6 and \frac{1}{2} to get \frac{13}{2}.

$$3x+\frac{13}{2}+\frac{8}{9}=100y+\frac{1}{2}-\frac{8}{10}\times 0.3$$

Add \frac{13}{2} and \frac{8}{9} to get \frac{133}{18}.

$$3x+\frac{133}{18}=100y+\frac{1}{2}-\frac{8}{10}\times 0.3$$

Reduce the fraction \frac{8}{10} to lowest terms by extracting and canceling out 2.

$$3x+\frac{133}{18}=100y+\frac{1}{2}-\frac{4}{5}\times 0.3$$

Multiply \frac{4}{5} and 0.3 to get \frac{6}{25}.

$$3x+\frac{133}{18}=100y+\frac{1}{2}-\frac{6}{25}$$

Subtract \frac{6}{25} from \frac{1}{2} to get \frac{13}{50}.

$$3x+\frac{133}{18}=100y+\frac{13}{50}$$

Subtract \frac{133}{18} from both sides.

$$3x=100y+\frac{13}{50}-\frac{133}{18}$$

Subtract \frac{133}{18} from \frac{13}{50} to get -\frac{1604}{225}.

$$3x=100y-\frac{1604}{225}$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{100y-\frac{1604}{225}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{100y-\frac{1604}{225}}{3}$$

Divide 100y-\frac{1604}{225} by 3.

$$x=\frac{100y}{3}-\frac{1604}{675}$$

Solve for y

$$y=\frac{3x}{100}+\frac{401}{5625}$$

Steps for Solving Linear Equation

Add 6 and \frac{1}{2} to get \frac{13}{2}.

$$3x+\frac{13}{2}+\frac{8}{9}=100y+\frac{1}{2}-\frac{8}{10}\times 0.3$$

Add \frac{13}{2} and \frac{8}{9} to get \frac{133}{18}.

$$3x+\frac{133}{18}=100y+\frac{1}{2}-\frac{8}{10}\times 0.3$$

Reduce the fraction \frac{8}{10} to lowest terms by extracting and canceling out 2.

$$3x+\frac{133}{18}=100y+\frac{1}{2}-\frac{4}{5}\times 0.3$$

Multiply \frac{4}{5} and 0.3 to get \frac{6}{25}.

$$3x+\frac{133}{18}=100y+\frac{1}{2}-\frac{6}{25}$$

Subtract \frac{6}{25} from \frac{1}{2} to get \frac{13}{50}.

$$3x+\frac{133}{18}=100y+\frac{13}{50}$$

Swap sides so that all variable terms are on the left hand side.

$$100y+\frac{13}{50}=3x+\frac{133}{18}$$

Subtract \frac{13}{50} from both sides.

$$100y=3x+\frac{133}{18}-\frac{13}{50}$$

Subtract \frac{13}{50} from \frac{133}{18} to get \frac{1604}{225}.

$$100y=3x+\frac{1604}{225}$$

Divide both sides by 100.

$$\frac{100y}{100}=\frac{3x+\frac{1604}{225}}{100}$$

Dividing by 100 undoes the multiplication by 100.

$$y=\frac{3x+\frac{1604}{225}}{100}$$

Divide 3x+\frac{1604}{225} by 100.

$$y=\frac{3x}{100}+\frac{401}{5625}$$