Solve for x
x=\frac{8-4y}{3}
Solve for y
y=-\frac{3x}{4}+2
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3x=8-4y
Subtract 4y from both sides.
\frac{3x}{3}=\frac{8-4y}{3}
Divide both sides by 3.
x=\frac{8-4y}{3}
Dividing by 3 undoes the multiplication by 3.
4y=8-3x
Subtract 3x from both sides.
\frac{4y}{4}=\frac{8-3x}{4}
Divide both sides by 4.
y=\frac{8-3x}{4}
Dividing by 4 undoes the multiplication by 4.
y=-\frac{3x}{4}+2
Divide 8-3x by 4.
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