Solve 3x+4<6x-12

$$3 x + 4 < 6 x - 12$$

Solve for x

$$x>\frac{16}{3}$$

Solution Steps

Subtract 6x from both sides.

$$3x+4-6x<-12$$

Combine 3x and -6x to get -3x.

$$-3x+4<-12$$

Subtract 4 from both sides.

$$-3x<-12-4$$

Subtract 4 from -12 to get -16.

$$-3x<-16$$

Divide both sides by -3. Since -3 is negative, the inequality direction is changed.

$$x>\frac{-16}{-3}$$

Fraction \frac{-16}{-3} can be simplified to \frac{16}{3} by removing the negative sign from both the numerator and the denominator.

$$x>\frac{16}{3}$$