Solve for x
x=\frac{2}{3}-y
Solve for y
y=\frac{2}{3}-x
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3x=2-3y
Subtract 3y from both sides.
\frac{3x}{3}=\frac{2-3y}{3}
Divide both sides by 3.
x=\frac{2-3y}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{2}{3}-y
Divide 2-3y by 3.
3y=2-3x
Subtract 3x from both sides.
\frac{3y}{3}=\frac{2-3x}{3}
Divide both sides by 3.
y=\frac{2-3x}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{2}{3}-x
Divide 2-3x by 3.
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