Solve for x
x=-\frac{2y}{3}+2z
Solve for y
y=-\frac{3x}{2}+3z
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3x-6z=-2y
Subtract 2y from both sides. Anything subtracted from zero gives its negation.
3x=-2y+6z
Add 6z to both sides.
3x=6z-2y
The equation is in standard form.
\frac{3x}{3}=\frac{6z-2y}{3}
Divide both sides by 3.
x=\frac{6z-2y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{2y}{3}+2z
Divide -2y+6z by 3.
2y-6z=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
2y=-3x+6z
Add 6z to both sides.
2y=6z-3x
The equation is in standard form.
\frac{2y}{2}=\frac{6z-3x}{2}
Divide both sides by 2.
y=\frac{6z-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}+3z
Divide -3x+6z by 2.
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