Solve for x
x=-\frac{2y}{3}+z+\frac{16}{3}
Solve for y
y=\frac{3z}{2}-\frac{3x}{2}+8
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3x-3z=16-2y
Subtract 2y from both sides.
3x=16-2y+3z
Add 3z to both sides.
3x=16+3z-2y
The equation is in standard form.
\frac{3x}{3}=\frac{16+3z-2y}{3}
Divide both sides by 3.
x=\frac{16+3z-2y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{2y}{3}+z+\frac{16}{3}
Divide 16-2y+3z by 3.
2y-3z=16-3x
Subtract 3x from both sides.
2y=16-3x+3z
Add 3z to both sides.
2y=16+3z-3x
The equation is in standard form.
\frac{2y}{2}=\frac{16+3z-3x}{2}
Divide both sides by 2.
y=\frac{16+3z-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=\frac{3z}{2}-\frac{3x}{2}+8
Divide 16-3x+3z by 2.
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