Solve for x
x=-\frac{2y}{3}+z+\frac{10}{3}
Solve for y
y=\frac{3z}{2}-\frac{3x}{2}+5
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3x-3z=10-2y
Subtract 2y from both sides.
3x=10-2y+3z
Add 3z to both sides.
3x=10+3z-2y
The equation is in standard form.
\frac{3x}{3}=\frac{10+3z-2y}{3}
Divide both sides by 3.
x=\frac{10+3z-2y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{2y}{3}+z+\frac{10}{3}
Divide 10-2y+3z by 3.
2y-3z=10-3x
Subtract 3x from both sides.
2y=10-3x+3z
Add 3z to both sides.
2y=10+3z-3x
The equation is in standard form.
\frac{2y}{2}=\frac{10+3z-3x}{2}
Divide both sides by 2.
y=\frac{10+3z-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=\frac{3z}{2}-\frac{3x}{2}+5
Divide 10-3x+3z by 2.
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