Solve for x
x=-\frac{2y}{3}+6
Solve for y
y=-\frac{3x}{2}+9
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3x-18=-2y
Subtract 2y from both sides. Anything subtracted from zero gives its negation.
3x=-2y+18
Add 18 to both sides.
3x=18-2y
The equation is in standard form.
\frac{3x}{3}=\frac{18-2y}{3}
Divide both sides by 3.
x=\frac{18-2y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{2y}{3}+6
Divide -2y+18 by 3.
2y-18=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
2y=-3x+18
Add 18 to both sides.
2y=18-3x
The equation is in standard form.
\frac{2y}{2}=\frac{18-3x}{2}
Divide both sides by 2.
y=\frac{18-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}+9
Divide -3x+18 by 2.
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