Solve for x
x=-\frac{z}{3}-\frac{2y}{3}+2
Solve for y
y=-\frac{z}{2}-\frac{3x}{2}+3
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3x+z=6-2y
Subtract 2y from both sides.
3x=6-2y-z
Subtract z from both sides.
3x=6-z-2y
The equation is in standard form.
\frac{3x}{3}=\frac{6-z-2y}{3}
Divide both sides by 3.
x=\frac{6-z-2y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{z}{3}-\frac{2y}{3}+2
Divide 6-2y-z by 3.
2y+z=6-3x
Subtract 3x from both sides.
2y=6-3x-z
Subtract z from both sides.
2y=6-z-3x
The equation is in standard form.
\frac{2y}{2}=\frac{6-z-3x}{2}
Divide both sides by 2.
y=\frac{6-z-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{z}{2}-\frac{3x}{2}+3
Divide 6-3x-z by 2.
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