Solve for x
x=\frac{20y+8}{3}
Solve for y
y=\frac{3x}{20}-\frac{2}{5}
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3x+2y+7-6x=-18y-1
Subtract 6x from both sides.
-3x+2y+7=-18y-1
Combine 3x and -6x to get -3x.
-3x+7=-18y-1-2y
Subtract 2y from both sides.
-3x+7=-20y-1
Combine -18y and -2y to get -20y.
-3x=-20y-1-7
Subtract 7 from both sides.
-3x=-20y-8
Subtract 7 from -1 to get -8.
\frac{-3x}{-3}=\frac{-20y-8}{-3}
Divide both sides by -3.
x=\frac{-20y-8}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{20y+8}{3}
Divide -20y-8 by -3.
3x+2y+7+18y=6x-1
Add 18y to both sides.
3x+20y+7=6x-1
Combine 2y and 18y to get 20y.
20y+7=6x-1-3x
Subtract 3x from both sides.
20y+7=3x-1
Combine 6x and -3x to get 3x.
20y=3x-1-7
Subtract 7 from both sides.
20y=3x-8
Subtract 7 from -1 to get -8.
\frac{20y}{20}=\frac{3x-8}{20}
Divide both sides by 20.
y=\frac{3x-8}{20}
Dividing by 20 undoes the multiplication by 20.
y=\frac{3x}{20}-\frac{2}{5}
Divide 3x-8 by 20.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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