Solve 3x+3/5<x+2

$$3 x + \frac { 3 } { 5 } < x + 2$$

Solve for x

$$x<\frac{7}{10}$$

Solution Steps

Subtract x from both sides.

$$3x+\frac{3}{5}-x<2$$

Combine 3x and -x to get 2x.

$$2x+\frac{3}{5}<2$$

Subtract \frac{3}{5} from both sides.

$$2x<2-\frac{3}{5}$$

Convert 2 to fraction \frac{10}{5}.

$$2x<\frac{10}{5}-\frac{3}{5}$$

Since \frac{10}{5} and \frac{3}{5} have the same denominator, subtract them by subtracting their numerators.

$$2x<\frac{10-3}{5}$$

Subtract 3 from 10 to get 7.

$$2x<\frac{7}{5}$$

Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.

$$x<\frac{\frac{7}{5}}{2}$$

Express \frac{\frac{7}{5}}{2} as a single fraction.

$$x<\frac{7}{5\times 2}$$

Multiply 5 and 2 to get 10.

$$x<\frac{7}{10}$$