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w^{2}\left(3w+5\right)+7\left(3w+5\right)
Do the grouping 3w^{3}+5w^{2}+21w+35=\left(3w^{3}+5w^{2}\right)+\left(21w+35\right), and factor out w^{2} in the first and 7 in the second group.
\left(3w+5\right)\left(w^{2}+7\right)
Factor out common term 3w+5 by using distributive property. Polynomial w^{2}+7 is not factored since it does not have any rational roots.