Solve 3t^2-12=9

$$3 t ^ { 2 } - 12 = 9$$

Solve for t

$$t=\sqrt{7}\approx 2.645751311$$

$$t=-\sqrt{7}\approx -2.645751311$$

Steps by Finding Square Root

Add 12 to both sides.

$$3t^{2}=9+12$$

Add 9 and 12 to get 21.

$$3t^{2}=21$$

Divide both sides by 3.

$$t^{2}=\frac{21}{3}$$

Divide 21 by 3 to get 7.

$$t^{2}=7$$

Take the square root of both sides of the equation.

$$t=\sqrt{7} t=-\sqrt{7}$$

Steps Using the Quadratic Formula

Subtract 9 from both sides.

$$3t^{2}-12-9=0$$

Subtract 9 from -12 to get -21.

$$3t^{2}-21=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and -21 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$t=\frac{0±\sqrt{0^{2}-4\times 3\left(-21\right)}}{2\times 3}$$

Square 0.

$$t=\frac{0±\sqrt{-4\times 3\left(-21\right)}}{2\times 3}$$

Multiply -4 times 3.

$$t=\frac{0±\sqrt{-12\left(-21\right)}}{2\times 3}$$

Multiply -12 times -21.

$$t=\frac{0±\sqrt{252}}{2\times 3}$$

Take the square root of 252.

$$t=\frac{0±6\sqrt{7}}{2\times 3}$$

Multiply 2 times 3.

$$t=\frac{0±6\sqrt{7}}{6}$$

Now solve the equation t=\frac{0±6\sqrt{7}}{6} when ± is plus.

$$t=\sqrt{7}$$

Now solve the equation t=\frac{0±6\sqrt{7}}{6} when ± is minus.

$$t=-\sqrt{7}$$

The equation is now solved.

$$t=\sqrt{7} t=-\sqrt{7}$$