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r\left(3r+18\right)=0
Factor out r.
r=0 r=-6
To find equation solutions, solve r=0 and 3r+18=0.
3r^{2}+18r=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
r=\frac{-18±\sqrt{18^{2}}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 18 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
r=\frac{-18±18}{2\times 3}
Take the square root of 18^{2}.
r=\frac{-18±18}{6}
Multiply 2 times 3.
r=\frac{0}{6}
Now solve the equation r=\frac{-18±18}{6} when ± is plus. Add -18 to 18.
r=0
Divide 0 by 6.
r=-\frac{36}{6}
Now solve the equation r=\frac{-18±18}{6} when ± is minus. Subtract 18 from -18.
r=-6
Divide -36 by 6.
r=0 r=-6
The equation is now solved.
3r^{2}+18r=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{3r^{2}+18r}{3}=\frac{0}{3}
Divide both sides by 3.
r^{2}+\frac{18}{3}r=\frac{0}{3}
Dividing by 3 undoes the multiplication by 3.
r^{2}+6r=\frac{0}{3}
Divide 18 by 3.
r^{2}+6r=0
Divide 0 by 3.
r^{2}+6r+3^{2}=3^{2}
Divide 6, the coefficient of the x term, by 2 to get 3. Then add the square of 3 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
r^{2}+6r+9=9
Square 3.
\left(r+3\right)^{2}=9
Factor r^{2}+6r+9. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(r+3\right)^{2}}=\sqrt{9}
Take the square root of both sides of the equation.
r+3=3 r+3=-3
Simplify.
r=0 r=-6
Subtract 3 from both sides of the equation.