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Solve for c
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4p+\frac{1}{2}p=18c
Combine 3p and p to get 4p.
\frac{9}{2}p=18c
Combine 4p and \frac{1}{2}p to get \frac{9}{2}p.
18c=\frac{9}{2}p
Swap sides so that all variable terms are on the left hand side.
18c=\frac{9p}{2}
The equation is in standard form.
\frac{18c}{18}=\frac{9p}{2\times 18}
Divide both sides by 18.
c=\frac{9p}{2\times 18}
Dividing by 18 undoes the multiplication by 18.
c=\frac{p}{4}
Divide \frac{9p}{2} by 18.
4p+\frac{1}{2}p=18c
Combine 3p and p to get 4p.
\frac{9}{2}p=18c
Combine 4p and \frac{1}{2}p to get \frac{9}{2}p.
\frac{\frac{9}{2}p}{\frac{9}{2}}=\frac{18c}{\frac{9}{2}}
Divide both sides of the equation by \frac{9}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.
p=\frac{18c}{\frac{9}{2}}
Dividing by \frac{9}{2} undoes the multiplication by \frac{9}{2}.
p=4c
Divide 18c by \frac{9}{2} by multiplying 18c by the reciprocal of \frac{9}{2}.