Solve 3mx+3=2(3-x)

$$3 m x + 3 = 2 ( 3 - x )$$

Solve for m

$$m=-\frac{2}{3}+\frac{1}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by 3-x.

$$3mx+3=6-2x$$

Subtract 3 from both sides.

$$3mx=6-2x-3$$

Subtract 3 from 6 to get 3.

$$3mx=3-2x$$

The equation is in standard form.

$$3xm=3-2x$$

Divide both sides by 3x.

$$\frac{3xm}{3x}=\frac{3-2x}{3x}$$

Dividing by 3x undoes the multiplication by 3x.

$$m=\frac{3-2x}{3x}$$

Divide 3-2x by 3x.

$$m=-\frac{2}{3}+\frac{1}{x}$$

Solve for x

$$x=\frac{3}{3m+2}$$

$$m\neq -\frac{2}{3}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by 3-x.

$$3mx+3=6-2x$$

Add 2x to both sides.

$$3mx+3+2x=6$$

Subtract 3 from both sides.

$$3mx+2x=6-3$$

Subtract 3 from 6 to get 3.

$$3mx+2x=3$$

Combine all terms containing x.

$$\left(3m+2\right)x=3$$

Divide both sides by 3m+2.

$$\frac{\left(3m+2\right)x}{3m+2}=\frac{3}{3m+2}$$

Dividing by 3m+2 undoes the multiplication by 3m+2.

$$x=\frac{3}{3m+2}$$