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Solve for z
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3iz=4+2i
Add 2i to both sides.
z=\frac{4+2i}{3i}
Divide both sides by 3i.
z=\frac{\left(4+2i\right)i}{3i^{2}}
Multiply both numerator and denominator of \frac{4+2i}{3i} by imaginary unit i.
z=\frac{\left(4+2i\right)i}{-3}
By definition, i^{2} is -1. Calculate the denominator.
z=\frac{4i+2i^{2}}{-3}
Multiply 4+2i times i.
z=\frac{4i+2\left(-1\right)}{-3}
By definition, i^{2} is -1.
z=\frac{-2+4i}{-3}
Do the multiplications in 4i+2\left(-1\right). Reorder the terms.
z=\frac{2}{3}-\frac{4}{3}i
Divide -2+4i by -3 to get \frac{2}{3}-\frac{4}{3}i.