Solve 3b*3a-3ay=6ab

$$3 b \cdot 3 a - 3 a y = 6 a b$$

Solve for a

$$\left\{\begin{matrix}\\a=0\text{, }&\text{unconditionally}\\a\in \mathrm{R}\text{, }&b=y\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply 3 and 3 to get 9.

$$9ba-3ay=6ab$$

Subtract 6ab from both sides.

$$9ba-3ay-6ab=0$$

Combine 9ba and -6ab to get 3ba.

$$3ba-3ay=0$$

Combine all terms containing a.

$$\left(3b-3y\right)a=0$$

Divide 0 by 3b-3y.

$$a=0$$

Solve for b

$$\left\{\begin{matrix}\\b=y\text{, }&\text{unconditionally}\\b\in \mathrm{R}\text{, }&a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply 3 and 3 to get 9.

$$9ba-3ay=6ab$$

Subtract 6ab from both sides.

$$9ba-3ay-6ab=0$$

Combine 9ba and -6ab to get 3ba.

$$3ba-3ay=0$$

Add 3ay to both sides. Anything plus zero gives itself.

$$3ba=3ay$$

Cancel out 3 on both sides.

$$ba=ay$$

The equation is in standard form.

$$ab=ay$$

Divide both sides by a.

$$\frac{ab}{a}=\frac{ay}{a}$$

Dividing by a undoes the multiplication by a.

$$b=\frac{ay}{a}$$

Divide ay by a.

$$b=y$$