Factor
\left(3b-7a\right)\left(4a+b^{2}\right)
Evaluate
\left(3b-7a\right)\left(4a+b^{2}\right)
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b^{2}\left(-7a+3b\right)+4a\left(-7a+3b\right)
Do the grouping 3b^{3}-7ab^{2}+12ab-28a^{2}=\left(3b^{3}-7ab^{2}\right)+\left(12ab-28a^{2}\right), and factor out b^{2} in the first and 4a in the second group.
\left(-7a+3b\right)\left(b^{2}+4a\right)
Factor out common term -7a+3b by using distributive property.
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