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3b+x^{2}=x^{2}+4x+4
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.
3b=x^{2}+4x+4-x^{2}
Subtract x^{2} from both sides.
3b=4x+4
Combine x^{2} and -x^{2} to get 0.
\frac{3b}{3}=\frac{4x+4}{3}
Divide both sides by 3.
b=\frac{4x+4}{3}
Dividing by 3 undoes the multiplication by 3.
3b+x^{2}=x^{2}+4x+4
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.
3b+x^{2}-x^{2}=4x+4
Subtract x^{2} from both sides.
3b=4x+4
Combine x^{2} and -x^{2} to get 0.
4x+4=3b
Swap sides so that all variable terms are on the left hand side.
4x=3b-4
Subtract 4 from both sides.
\frac{4x}{4}=\frac{3b-4}{4}
Divide both sides by 4.
x=\frac{3b-4}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{3b}{4}-1
Divide 3b-4 by 4.