Solve 3a*ab-2a^2*(-4b)-8*(2a^2b)=

$$3 a \cdot a b - 2 a ^ { 2 } \cdot ( - 4 b ) - 8 \cdot ( 2 a ^ { 2 } b ) =$$

Evaluate

$$-5ba^{2}$$

Solution Steps

Multiply a and a to get a^{2}.

$$3a^{2}b-2a^{2}\left(-4\right)b-8\times 2a^{2}b$$

Multiply 2 and -4 to get -8.

$$3a^{2}b-\left(-8a^{2}b\right)-8\times 2a^{2}b$$

The opposite of -8a^{2}b is 8a^{2}b.

$$3a^{2}b+8a^{2}b-8\times 2a^{2}b$$

Combine 3a^{2}b and 8a^{2}b to get 11a^{2}b.

$$11a^{2}b-8\times 2a^{2}b$$

Multiply 8 and 2 to get 16.

$$11a^{2}b-16a^{2}b$$

Combine 11a^{2}b and -16a^{2}b to get -5a^{2}b.

$$-5a^{2}b$$

Differentiate w.r.t. b

$$-5a^{2}$$