Solve 3a^2b^2*9ab^2

$$3 a ^ { 2 } b ^ { 2 } \cdot 9 a b ^ { 2 }$$

Evaluate

$$27a^{3}b^{4}$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$3^{1}a^{2}b^{2}\times 9^{1}a^{1}b^{2}$$

Use the Commutative Property of Multiplication.

$$3^{1}\times 9^{1}a^{2}a^{1}b^{2}b^{2}$$

To multiply powers of the same base, add their exponents.

$$3^{1}\times 9^{1}a^{2+1}b^{2+2}$$

Add the exponents 2 and 1.

$$3^{1}\times 9^{1}a^{3}b^{2+2}$$

Add the exponents 2 and 2.

$$3^{1}\times 9^{1}a^{3}b^{4}$$

Multiply 3 times 9.

$$27a^{3}b^{4}$$

Differentiate w.r.t. a

$$81a^{2}b^{4}$$