Solve for a
a=\frac{10-2b}{3}
Solve for b
b=-\frac{3a}{2}+5
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3a=10-2b
Subtract 2b from both sides.
\frac{3a}{3}=\frac{10-2b}{3}
Divide both sides by 3.
a=\frac{10-2b}{3}
Dividing by 3 undoes the multiplication by 3.
2b=10-3a
Subtract 3a from both sides.
\frac{2b}{2}=\frac{10-3a}{2}
Divide both sides by 2.
b=\frac{10-3a}{2}
Dividing by 2 undoes the multiplication by 2.
b=-\frac{3a}{2}+5
Divide 10-3a by 2.
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