Solve 3-2xgeqx+2

$$3 - 2 x \geq x + 2$$

Solve for x

$$x\leq \frac{1}{3}$$

Solution Steps

Subtract x from both sides.

$$3-2x-x\geq 2$$

Combine -2x and -x to get -3x.

$$3-3x\geq 2$$

Subtract 3 from both sides.

$$-3x\geq 2-3$$

Subtract 3 from 2 to get -1.

$$-3x\geq -1$$

Divide both sides by -3. Since -3 is negative, the inequality direction is changed.

$$x\leq \frac{-1}{-3}$$

Fraction \frac{-1}{-3} can be simplified to \frac{1}{3} by removing the negative sign from both the numerator and the denominator.

$$x\leq \frac{1}{3}$$