Solve 3 - ∫ x^4/3 wrt x=3x^3/3/5+c

$$3 - \int x ^ { 4 / 3 } d x = \frac { 3 x ^ { 3 / 3 } } { 5 } + c$$

Solve for c

$$c=-\frac{3x^{\frac{7}{3}}}{7}-\frac{3x}{5}-С+3$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 5.

$$15-5\int x^{\frac{4}{3}}\mathrm{d}x=3x^{\frac{3}{3}}+5c$$

Divide 3 by 3 to get 1.

$$15-5\int x^{\frac{4}{3}}\mathrm{d}x=3x^{1}+5c$$

Calculate x to the power of 1 and get x.

$$15-5\int x^{\frac{4}{3}}\mathrm{d}x=3x+5c$$

Swap sides so that all variable terms are on the left hand side.

$$3x+5c=15-5\int x^{\frac{4}{3}}\mathrm{d}x$$

Subtract 3x from both sides.

$$5c=15-5\int x^{\frac{4}{3}}\mathrm{d}x-3x$$

The equation is in standard form.

$$5c=-\frac{15x^{\frac{7}{3}}}{7}-3x-5С+15$$

Divide both sides by 5.

$$\frac{5c}{5}=\frac{-\frac{15x^{\frac{7}{3}}}{7}-3x-5С+15}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$c=\frac{-\frac{15x^{\frac{7}{3}}}{7}-3x-5С+15}{5}$$

Divide 15-\frac{15x^{\frac{7}{3}}}{7}-5С-3x by 5.

$$c=-\frac{3x^{\frac{7}{3}}}{7}-\frac{3x}{5}-С+3$$