Solve 3-2/3(x+1)=1/2x

$$3 - \frac { 2 } { 3 } ( x + 1 ) = \frac { 1 } { 2 } x$$

Solve for x

$$x=2$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{2}{3} by x+1.

$$3-\frac{2}{3}x-\frac{2}{3}=\frac{1}{2}x$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{9}{3}-\frac{2}{3}x-\frac{2}{3}=\frac{1}{2}x$$

Since \frac{9}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-2}{3}-\frac{2}{3}x=\frac{1}{2}x$$

Subtract 2 from 9 to get 7.

$$\frac{7}{3}-\frac{2}{3}x=\frac{1}{2}x$$

Subtract \frac{1}{2}x from both sides.

$$\frac{7}{3}-\frac{2}{3}x-\frac{1}{2}x=0$$

Combine -\frac{2}{3}x and -\frac{1}{2}x to get -\frac{7}{6}x.

$$\frac{7}{3}-\frac{7}{6}x=0$$

Subtract \frac{7}{3} from both sides. Anything subtracted from zero gives its negation.

$$-\frac{7}{6}x=-\frac{7}{3}$$

Multiply both sides by -\frac{6}{7}, the reciprocal of -\frac{7}{6}.

$$x=-\frac{7}{3}\left(-\frac{6}{7}\right)$$

Multiply -\frac{7}{3} times -\frac{6}{7} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-7\left(-6\right)}{3\times 7}$$

Do the multiplications in the fraction \frac{-7\left(-6\right)}{3\times 7}.

$$x=\frac{42}{21}$$

Divide 42 by 21 to get 2.

$$x=2$$