Solve 3(y-3)<7y-24

$$3 ( y - 3 ) < 7 y - 24$$

Solve for y

$$y>\frac{15}{4}$$

Solution Steps

Use the distributive property to multiply 3 by y-3.

$$3y-9<7y-24$$

Subtract 7y from both sides.

$$3y-9-7y<-24$$

Combine 3y and -7y to get -4y.

$$-4y-9<-24$$

Add 9 to both sides.

$$-4y<-24+9$$

Add -24 and 9 to get -15.

$$-4y<-15$$

Divide both sides by -4. Since -4 is negative, the inequality direction is changed.

$$y>\frac{-15}{-4}$$

Fraction \frac{-15}{-4} can be simplified to \frac{15}{4} by removing the negative sign from both the numerator and the denominator.

$$y>\frac{15}{4}$$