Solve 3(x-5)-2geq-4(-3+8)+4

$$3 ( x - 5 ) - 2 \geq - 4 ( - 3 + 8 ) + 4$$

Solve for x

$$x\geq \frac{1}{3}$$

Solution Steps

Use the distributive property to multiply 3 by x-5.

$$3x-15-2\geq -4\left(-3+8\right)+4$$

Subtract 2 from -15 to get -17.

$$3x-17\geq -4\left(-3+8\right)+4$$

Add -3 and 8 to get 5.

$$3x-17\geq -4\times 5+4$$

Multiply -4 and 5 to get -20.

$$3x-17\geq -20+4$$

Add -20 and 4 to get -16.

$$3x-17\geq -16$$

Add 17 to both sides.

$$3x\geq -16+17$$

Add -16 and 17 to get 1.

$$3x\geq 1$$

Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$x\geq \frac{1}{3}$$