Solve 3(x-1)geq1

$$3 ( x - 1 ) \geq 1$$

Solve for x

$$x\geq \frac{4}{3}$$

Solution Steps

Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$x-1\geq \frac{1}{3}$$

Add 1 to both sides.

$$x\geq \frac{1}{3}+1$$

Convert 1 to fraction \frac{3}{3}.

$$x\geq \frac{1}{3}+\frac{3}{3}$$

Since \frac{1}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$x\geq \frac{1+3}{3}$$

Add 1 and 3 to get 4.

$$x\geq \frac{4}{3}$$