Solve 3(x^2-2x+1)-x(3x-4)=5

$$3 ( x ^ { 2 } - 2 x + 1 ) - x ( 3 x - 4 ) = 5$$

Solve for x

$$x=-1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by x^{2}-2x+1.

$$3x^{2}-6x+3-x\left(3x-4\right)=5$$

Use the distributive property to multiply x by 3x-4.

$$3x^{2}-6x+3-\left(3x^{2}-4x\right)=5$$

To find the opposite of 3x^{2}-4x, find the opposite of each term.

$$3x^{2}-6x+3-3x^{2}+4x=5$$

Combine 3x^{2} and -3x^{2} to get 0.

$$-6x+3+4x=5$$

Combine -6x and 4x to get -2x.

$$-2x+3=5$$

Subtract 3 from both sides.

$$-2x=5-3$$

Subtract 3 from 5 to get 2.

$$-2x=2$$

Divide both sides by -2.

$$x=\frac{2}{-2}$$

Divide 2 by -2 to get -1.

$$x=-1$$