Solve for b (complex solution)
\left\{\begin{matrix}b=\frac{c-6}{x}\text{, }&x\neq 0\\b\in \mathrm{C}\text{, }&c=6\text{ and }x=0\end{matrix}\right.
Solve for b
\left\{\begin{matrix}b=\frac{c-6}{x}\text{, }&x\neq 0\\b\in \mathrm{R}\text{, }&c=6\text{ and }x=0\end{matrix}\right.
Solve for c
c=bx+6
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c-bx=\frac{18}{3}
Divide both sides by 3.
c-bx=6
Divide 18 by 3 to get 6.
-bx=6-c
Subtract c from both sides.
\left(-x\right)b=6-c
The equation is in standard form.
\frac{\left(-x\right)b}{-x}=\frac{6-c}{-x}
Divide both sides by -x.
b=\frac{6-c}{-x}
Dividing by -x undoes the multiplication by -x.
b=\frac{c-6}{x}
Divide -c+6 by -x.
c-bx=\frac{18}{3}
Divide both sides by 3.
c-bx=6
Divide 18 by 3 to get 6.
-bx=6-c
Subtract c from both sides.
\left(-x\right)b=6-c
The equation is in standard form.
\frac{\left(-x\right)b}{-x}=\frac{6-c}{-x}
Divide both sides by -x.
b=\frac{6-c}{-x}
Dividing by -x undoes the multiplication by -x.
b=\frac{c-6}{x}
Divide 6-c by -x.
c-bx=\frac{18}{3}
Divide both sides by 3.
c-bx=6
Divide 18 by 3 to get 6.
c=6+bx
Add bx to both sides.
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