Solve for a
a\in \mathrm{R}
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3a+18=6\left(a+3\right)-3a
Use the distributive property to multiply 3 by a+6.
3a+18=6a+18-3a
Use the distributive property to multiply 6 by a+3.
3a+18=3a+18
Combine 6a and -3a to get 3a.
3a+18-3a=18
Subtract 3a from both sides.
18=18
Combine 3a and -3a to get 0.
\text{true}
Compare 18 and 18.
a\in \mathrm{R}
This is true for any a.
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