Solve 3(32+x)-4(3z-x)=10

$$3 ( 32 + x ) - 4 ( 3 z - x ) = 10$$

Solve for x

$$x=\frac{12z-86}{7}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by 32+x.

$$96+3x-4\left(3z-x\right)=10$$

Use the distributive property to multiply -4 by 3z-x.

$$96+3x-12z+4x=10$$

Combine 3x and 4x to get 7x.

$$96+7x-12z=10$$

Subtract 96 from both sides.

$$7x-12z=10-96$$

Subtract 96 from 10 to get -86.

$$7x-12z=-86$$

Add 12z to both sides.

$$7x=-86+12z$$

The equation is in standard form.

$$7x=12z-86$$

Divide both sides by 7.

$$\frac{7x}{7}=\frac{12z-86}{7}$$

Dividing by 7 undoes the multiplication by 7.

$$x=\frac{12z-86}{7}$$

Solve for z

$$z=\frac{7x}{12}+\frac{43}{6}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by 32+x.

$$96+3x-4\left(3z-x\right)=10$$

Use the distributive property to multiply -4 by 3z-x.

$$96+3x-12z+4x=10$$

Combine 3x and 4x to get 7x.

$$96+7x-12z=10$$

Subtract 96 from both sides.

$$7x-12z=10-96$$

Subtract 96 from 10 to get -86.

$$7x-12z=-86$$

Subtract 7x from both sides.

$$-12z=-86-7x$$

The equation is in standard form.

$$-12z=-7x-86$$

Divide both sides by -12.

$$\frac{-12z}{-12}=\frac{-7x-86}{-12}$$

Dividing by -12 undoes the multiplication by -12.

$$z=\frac{-7x-86}{-12}$$

Divide -86-7x by -12.

$$z=\frac{7x}{12}+\frac{43}{6}$$